Hello, I am new to using the FFTW algorithms in C++, and need some help getting started. I have used matlab (and done a good deal of C++) for many years, and I am rewriting some of my matlab code in C++ to see if it helps with speed/memory issues. I'll give an overview of what I'm trying to do, and see if anyone has suggestions. So, I am reading in a MAT file, and the data I want is stored in a 3D array. Matlab arrays are represented in fortran (column-first) format, which is not what FFTW uses, but I think that can be overcome by specifying the fftw plan slightly differently. The data contains epoched EEG data, where the dimensions are [samples, channels, trials]. For example, the array might consist of 40 trials, each with 64 channels, and each of these with 3000 samples, therefore with dimensions of [3000, 64, 40], for a total of 7,680,000 double elements. I want to calculate the spectrogram along the samples dimension; I am using the matlab definition of spectrogram, where I specify the window length, overlap, and size of the FFT. A moving window is applied, taking the DFT for each window (padding zeros when necessary). The dimensions of the output are then [freqs, samples, channels, trials], where freqs is nfft/2+1, the times are the number of samples (dependent on the window length and overlap), and channels and trials are unchanged. There are a few methods of doing this (I hope...) (1) The initial thought on how to do this is to basically pound it out in several for loops. For each trial and channel, I take winLen samples (say 100), pad to nfft (say 512), do the DFT via FFTW, get the magnitude and remove redundant data (so I'm left with 257 samples), move ahead overlap samples, and wash-rinse-repeat. This is intuitively the simplest, and probably where I want to start, but I do not know how do accomplish this using the fftw interfaces. With FFTW, I know I create a plan, in this case using fftw_plan_dft_r2c_1d, passing the fft length, input array pointer, output array pointer, and flags. My confusion is about the fact that I will be doing this thousands of times on different data, and I think that I do not need to recreate the plan every time, but how is that accomplished? The way I'm envisioning it, I create the plan using the FFTW_MEASURE flag, then use fftw_execute repeatedly, changing the contents of the input array (not the pointer value, but the contents of the array) in between every execute. Also, does the input array in the create plan function need to have valid data (ie the first chunk of data), or is it finding the optimal algorithm based on the size of the FFT alone? I think I'm primarily getting confused by the wording of the FFTW manual, where it says things like "To apply a given plan to a different array, use can use the guru interface." By different array, does that mean that the original contents of x have changed, or that the pointer x itself has changed? If the size of the data is not changing, it seems pretty inefficient to recalculate the plan for every step. (Again, I'm not familiar with FFTW, so any example code that shows EXACTLY how to do this would be very appreciated.) (2) How do the multidimensional functions work? If you are familiar with matlab, if I have a 2D array X, of size 100 x 50, for example, and I use the fft function like: fft(X, 512, 2), the function calculates the fft along the 2nd dimension, returning an array of size 100x512. (If I do fft(X, 512, 1) or fft(X,512), the returned answer is 512x50). Is this possible with FFTW? The spectrogram function works this way in matlab, where it takes a 1D vector of data, creates a 2D array based on the winLen and overlap, and takes the FFT down the winLen dimension. (3) Again, for the multidemensional functions, would it be possible to do the fft of an entire 4D array, only along a specified dimension? This would be similar to the matlab spectrogram, but not limited to a 2D array. I really appreciate anyone who takes the time to wade through this series of questions. Any help you can give me is obviously of tremendous help. Thanks! Adam

# new to FFTW - I have some questions

Started by ●February 16, 2006

Reply by ●February 16, 20062006-02-16

jawilson wrote:> plan every time, but how is that accomplished? The way I'm envisioning > it, I create the plan using the FFTW_MEASURE flag, then use > fftw_execute repeatedly, changing the contents of the input array (not > the pointer value, but the contents of the array) in between every > execute.Yes, that's how we envision FFTW being normally used when repeated FFTs are required.> Also, does the input array in the create plan function need to > have valid data (ie the first chunk of data), or is it finding the > optimal algorithm based on the size of the FFT alone?The input to create_plan does not have to have any valid data, but it does get overwritten during planning in FFTW_MEASURE or FFTW_PATIENT mode. This is described in the manual.> I think I'm > primarily getting confused by the wording of the FFTW manual, where it > says things like "To apply a given plan to a different array, use can > use the guru interface." By different array, does that mean that the > original contents of x have changed, or that the pointer x itself has > changed?If you just change the contents of x, then you can use the same plan. You can use the guru interface if you want to apply the plan to a different array (different pointer) of the same size etc.> I use the fft function like: fft(X, 512, 2), the function calculates > the fft along the 2nd dimension, returning an array of size 100x512. > (If I do fft(X, 512, 1) or fft(X,512), the returned answer is 512x50). > Is this possible with FFTW?FFTW won't do zero-padding for you, but it can transform just one dimension of an array using the advanced or guru interface. e.g. if you have an M x N array, stored in row-major order, and you want to only FFT the columns (the N dimension), then you would call the advanced interface to do an FFT of size N with howmany=M, stride=1, and dist=N. See the manual for more information.> (3) Again, for the multidemensional functions, would it be possible to > do the fft of an entire 4D array, only along a specified dimension? > This would be similar to the matlab spectrogram, but not limited to a > 2D array.Yes. In general if you have a 4D array and want to transform only an "interior" dimension (i.e. not the first or last dimension), then you need to use the guru interface. The reason is that transforming an interior dimension corresponds to a double loop of transforms, not a single loop. (Think about it.) For an answer to a similar question, where someone wanted to transform the middle dimension of a 3D array, see: http://groups.google.com/group/comp.lang.fortran/msg/463235d14226650d Cordially, Steven G. Johnson

Reply by ●February 16, 20062006-02-16

Reply by ●February 17, 20062006-02-17

Ok, I think I'm almost there. If I have a 4D array, with dimensions of: [40, 64, 20, 512], and I want to calculate the FFT of the last dimension, how do I set up the howmany_rank structure to do this? The pseudocode for what I want to do would be: data = double[40*64*20*512]; y = double[40*64*20*512]; ... for (tr = 0; tr < 40; tr++) for (ch = 0; ch < 64; ch++) for (col = 0; col < 20; col++) for (n=0; n < 512; n++) // this is obviously not how to access the data, but this is for clarity x = data[tr, ch, col, n]; y = fft(x); How is the howmany_dims array configured to do this series of for loops? Thanks! Adam

Reply by ●February 17, 20062006-02-17

Just found a small error in the above pseudocode; here is what it should have been: data = double[40*64*20*512]; y = double[40*64*20*512]; ... for (tr = 0; tr < 40; tr++) for (ch = 0; ch < 64; ch++) for (col = 0; col < 20; col++) for (n=0; n < 512; n++) x = data[tr, ch, col, n]; y = fft(x); Adam

Reply by ●February 17, 20062006-02-17

I found another error; I'm using the r2c with real data, so the output dimensions (the y array) should be: [40, 64, 20, 257] Also, the last line of pseudocode above should probably be (in matlab syntax): y(tr, ch, col, :) = fft(x); So, the plan I'm using is: plan = fftw_plan_guru_split_dft_r2c( 4, dims, // rank and dims 4, ???, // don't know how to setup howmany_dims x, y_re, y_im, FLAGS); Hopefully this makes a little more sense now. Adam

Reply by ●February 17, 20062006-02-17

> for (tr = 0; tr < 40; tr++) > for (ch = 0; ch < 64; ch++) > for (col = 0; col < 20; col++) > for (n=0; n < 512; n++) > x = data[tr, ch, col, n]; > y = fft(x);I'm assuming that your array is stored in row-major order as 40x64x20x512. Then the three loops you want correspond to: howmany_rank = 3; howmany_dims[0].n = 40; howmany_dims[0].is = howmany_dims[0].os = 64*20*512; howmany_dims[1].n = 64; howmany_dims[1].is = howmany_dims[0].os = 20*512; howmany_dims[2].n = 20; howmany_dims[2].is = howmany_dims[0].os = 512; Your transform is then 1d (rank=1) with dims[0].n = 512 and dims[0].is = dims[0].os = 1. Actually, in this particular case where you are transforming the *last* dimension, the three loops can be coalesced into a single loop, but FFTW will do this automatically internally. See also the section in the FFTW manual on multi-dimensional array format for more explanation: http://www.fftw.org/doc/Multi_002ddimensional-Array-Format.html Steven G. Johnson PS. It's more complicated if you have real data and want to use FFTW's r2c plans. In that case the strides are in units of real numbers instead of complex numbes so you have to multiply by 2, and furthermore the output is slightly bigger than the input so 512 is replaced by 514 to account for this as described in the manual (assuming you are operating in-place). See the manual.

Reply by ●February 17, 20062006-02-17

This is great! The data is in row major format. Also, I think I mentioned that I'm using the split format, so the output should be two arrays (real and imaginary) of 257 (correct?) This is what you said more or less, but with the complex format, it goes [re][im][re][im]... I'm going to try this out this weekend. Thanks for the help, and the great signal processing resource! Adam