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`135^(@)``90^(@)``60^(@)``120^(@)`

Answer :

DSolution :

(D) The angle between them should be `120^(@)` because in that case the figure formed by the intersection point of pair of tangent, the two end ponits of those two radii ( at which tangent are drawn ) and the centre of the circles is a quadrilateral. <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/ARH_NCERT_EXE_MATH_X_C10_S01_006_S01.png" width="80%"> <br> From figure it is quadrilateral, <br> `anglePOQ+anglePRQ=180^(@)` [`:.` sum of opposite angles are `180^(@)`] <br> `60^(@)+ theta=180^(@)` <br> `:. theta=120` <br> Hence, the required angle between them is `120^(@)`.